My Math Forum USE REAL NUMBER AXIOMS TO PROVE THAT (-1).(-1)=1 -Urgent-

 Real Analysis Real Analysis Math Forum

 November 17th, 2013, 07:31 AM #1 Newbie   Joined: Nov 2013 Posts: 6 Thanks: 0 USE REAL NUMBER AXIOMS TO PROVE THAT (-1).(-1)=1 -Urgent- i am having a hard time figuring this out, using the real number axioms to prove that (-1)x(-1)=1 please ,anybody help, i'll be eternally grateful
 November 17th, 2013, 07:47 AM #2 Senior Member   Joined: Jun 2013 From: London, England Posts: 1,316 Thanks: 116 Re: USE REAL NUMBER AXIOMS TO PROVE THAT (-1).(-1)=1 -Urgent Assuming you can prove that a(0) = 0, we have: 0 = (-1)(0) = (-1)(1-1) = -1(1)+ (-1)(-1) = -1 + (-1)(-1) So (-1)(-1) = -(-1) = 1
 November 17th, 2013, 07:53 AM #3 Newbie   Joined: Nov 2013 Posts: 6 Thanks: 0 Re: USE REAL NUMBER AXIOMS TO PROVE THAT (-1).(-1)=1 -Urgent Thank YOU VERY MUCH!! I finally get axioms now!, thanks you very much pero

 Tags 111, axioms, number, prove, real, urgent

,

# proof that (-1)*(-1)=1

Click on a term to search for related topics.
 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post xdeimos99 Real Analysis 2 October 16th, 2013 12:34 PM PlayingSolo Real Analysis 8 September 10th, 2012 11:46 AM asghar1992 Applied Math 3 December 3rd, 2011 02:52 PM TsAmE Complex Analysis 1 October 18th, 2010 04:38 PM david.west97 Number Theory 1 April 20th, 2009 06:15 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top