My Math Forum

My Math Forum (http://mymathforum.com/math-forums.php)
-   Real Analysis (http://mymathforum.com/real-analysis/)
-   -   Sequence convergence proof (http://mymathforum.com/real-analysis/3932-sequence-convergence-proof.html)

zve5 September 24th, 2008 11:25 AM

Sequence convergence proof
 
So i have this problem that asks to prove that the following sequence convergences, and find it its limit.
a1=sqrt (1)
a2= sqrt (1+sqrt1)
a3= sqrt ( 1+sqrt(1+sqrt(1)))
a4= sqrt (1+sqrt(1+sqrt(1+sqrt(1))))

babyRudin September 24th, 2008 12:23 PM

Re: Sequence convergence proof
 
First. You show that this sequence is strictly increasing (use induction).

If sqrt 1 < sqrt (1+sqrt 1) means s1<s2, then hypothesize sn < sn+1.

Use induction again to show that it is bounded above. ex. s1 = sqrt 1 < 2.
If sn <2 then sn+1 = sqrt(1+sn) < sqrt (1+2) < 2...
This isn't the tightest form of this, but we've shown that {sn} is increasing and bounded above.

This means that {sn} must converge to some number s. We know that it is less than or equal to whatever
you show it to be bounded by. Be careful about when it could be equal to this upper bound. Note we could have said
that it is bounded above several numbers. This doesn't mean the sequence will converge to it.

CRGreathouse September 24th, 2008 02:32 PM

Re: Sequence convergence proof
 
The above post shows how to prove that the sequence has a limit. To show what the limit is, substitute the expression into itself:

x = sqrt(1 + sqrt(1 + sqrt(1 + ...)))
x = sqrt(1 + x)


All times are GMT -8. The time now is 12:15 PM.

Copyright © 2019 My Math Forum. All rights reserved.