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 May 16th, 2019, 05:37 AM #1 Senior Member   Joined: Dec 2015 From: somewhere Posts: 510 Thanks: 79 Range of N Find the range of N such that $\displaystyle 1+\frac{1}{2}+...+\frac{1}{N} >(1+\frac{1}{N})^{N}$ .
 May 16th, 2019, 07:22 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,623 Thanks: 2076 Apparently, $N > 6$. Thanks from idontknow
 May 17th, 2019, 04:33 AM #3 Senior Member   Joined: Dec 2015 From: somewhere Posts: 510 Thanks: 79 To save time and use less complicated symbols I will post the solution in short-terms : Using (*)$\displaystyle H_{2^{N}} \geq 1+\frac{N}{2}$ ; $\displaystyle (1+1/N)^{N}$ is close(bounded) to 2 and 3 for integers . Let m be the mean value of number of terms of $\displaystyle H_{N}$ with condition(*) . For the bound close to 2 , $\displaystyle N=4$ ; For the bound close to 3 , $\displaystyle N=8$. Now $\displaystyle m=\lfloor \frac{b_1 + b_2 }{2} \rfloor =\lfloor \frac{8+4}{2}\rfloor=12/2=6$ , so $\displaystyle N>6$. Thanks from topsquark Last edited by idontknow; May 17th, 2019 at 04:44 AM.

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