June 17th, 2018, 04:39 AM  #1 
Member Joined: Oct 2012 Posts: 70 Thanks: 0  infinite series
Find 3/13+33/13^2+333/13^3+3333/13^4+.... 
June 17th, 2018, 06:35 AM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,266 Thanks: 1198 
write the series as $\displaystyle \sum \limits_{k=1} \dfrac{10^k1}{3\cdot 13^k}$ this is then the scaled difference of two geometric series whose values should be easy enough to compute. 

Tags 
infinite, series 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Infinite Series  Etyucan  Calculus  3  December 26th, 2012 03:15 AM 
Infinite series  Dragonkiller  Complex Analysis  4  August 2nd, 2012 03:30 PM 
Infinite series : 1/r^r  Zeefinity  Real Analysis  4  August 29th, 2011 12:18 AM 
Infinite Series  wannabe1  Real Analysis  2  December 1st, 2010 03:31 PM 
Infinite series : 1/2^(n^2)  Zeefinity  Real Analysis  3  April 22nd, 2010 10:58 PM 