My Math Forum Continuity of a Function

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 March 21st, 2018, 06:49 AM #1 Senior Member   Joined: Nov 2015 From: hyderabad Posts: 232 Thanks: 2 Continuity of a Function The points of continuity of the function $f:R -> R$ defined by $f(x) =${ $|x^2-1|,$ if $x$ is irrational $0$, if $x$ is rational are a) $x= -1, x=0, x=1$ b) $x=-1, x=1$ c) $x=-1, x=0$ d) $x=0, x=1$ How to solve this type of question when rationals & irrationals are given as the condition. Thank you
 March 21st, 2018, 09:36 AM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,202 Thanks: 1157 1) use the usual epsilon-delta proof 2) note that due to denseness of the reals in the rationals (and vice versa), rational and irrational numbers can be found arbitrarily close together. 3) Thus the only points where $f$ will be continuous is where the value of $f$ is equal for both rationals and irrationals 4) There are only two points where this will be true, and they are rather trivial to find. See if you can figure it out. Thanks from Lalitha183
March 22nd, 2018, 04:42 AM   #3
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 Originally Posted by romsek 1) use the usual epsilon-delta proof 2) note that due to denseness of the reals in the rationals (and vice versa), rational and irrational numbers can be found arbitrarily close together. 3) Thus the only points where $f$ will be continuous is where the value of $f$ is equal for both rationals and irrationals 4) There are only two points where this will be true, and they are rather trivial to find. See if you can figure it out.
3rd point helped me alot Thank you.
The points of continuity are $x=1$ & $x=-1$

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