My Math Forum Let $f(x) = 0$ ; $x \epsilon R-${$0,1$}.

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 March 16th, 2018, 05:56 PM #1 Senior Member   Joined: Nov 2015 From: hyderabad Posts: 232 Thanks: 2 Let $f(x) = 0$ ; $x \epsilon R-${$0,1$}. Let $f(x) = 0$ ; $x \epsilon R-\{0,1\}$. Then a) $f$ is discontinuous at $0$ and $1$ b) $f$ is continuous but not differentiable at $0$ and $1$ c) $f$ is differentiable at $0$ and $1$ but $f'$ is not continuous at $0$ and $1$ d) none of the above If $f'(x) =0$, then is it continuous? Only option (c) I have doubt. If yes, then the answer would be option (d). Last edited by skipjack; August 8th, 2018 at 06:56 PM.
 March 16th, 2018, 06:22 PM #2 Senior Member   Joined: Sep 2016 From: USA Posts: 444 Thanks: 254 Math Focus: Dynamical systems, analytic function theory, numerics I suppose you mean $f(x) = 0$ for $x \in \mathbb{R} - \{0,1\}$? If so, then the answer should be (d). You should find examples which violate each of (a)-(c). Also, $f'(x) = 0$ is not necessary for any examples, nor does this assumption make any of the claims true. I'm not even sure how it's related. Thanks from Lalitha183 Last edited by skipjack; August 8th, 2018 at 06:57 PM.
March 16th, 2018, 06:29 PM   #3
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 Originally Posted by SDK I suppose you mean $f(x) = 0$ for $x \in \mathbb{R} - \{0,1\}$? If so, then the answer should be (d). You should find examples which violate each of (a)-(c). Also, $f'(x) = 0$ is not necessary for any examples, nor does this assumption make any of the claims true. I'm not even sure how it's related.
Thanks for the help. I have checked that the function is differentiable at $0$. In the option (c), it says $f'(x)$ is not continuous at $0$ and $1$. I have $f(x)$ as $0$. So I thought if it is continuous or not in case of $f'(x)$.

Last edited by skipjack; August 8th, 2018 at 06:59 PM.

 August 8th, 2018, 03:58 AM #4 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,261 Thanks: 894 I assume that "x∈R−{0,1}" means that f is not defined at 0 and 1. In that case it is not continuous so not differentiable there.
 August 8th, 2018, 01:15 PM #5 Global Moderator   Joined: May 2007 Posts: 6,589 Thanks: 612 If f(x) is not defined at 0 or 1, then d) applies for lack of information.
 August 8th, 2018, 07:09 PM #6 Global Moderator   Joined: Dec 2006 Posts: 19,546 Thanks: 1754 What information did you have in mind for choice (a)?

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