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 December 9th, 2017, 07:56 AM #1 Senior Member   Joined: Jan 2015 From: usa Posts: 104 Thanks: 1 Inequality Let $\nu>1$ be a parameter. For all $t>0,\;\;\;$ we consider $A(t)=\frac{1-cos(t\sqrt{4\nu-1})}{4\nu-1}-(\cosh(t)-1)$ $g(t)=\frac{2A(t)}{\frac{sin(t\sqrt{4\nu-1})}{\sqrt{4\nu-1}}+\sinh(t)+A(t)}$ $f(t)=\frac{\sqrt{\nu }\;t^{\frac{3}{2}}\;e^{-t\nu^\frac{1}{3}}}{ln(1-g(t))}$ >I want to prove that there exists a constant $c>0$ which dosn't depend on the parameter $\nu$ such that: $$f(t)\le c$$ for all $t>0$ Please help me to do so. Thanks. Last edited by mona123; December 9th, 2017 at 08:33 AM. Tags inequality Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post StillAlive Calculus 5 September 2nd, 2016 11:45 PM Dacu Algebra 10 April 6th, 2014 06:27 PM Ionika Algebra 0 February 17th, 2014 02:29 AM JC Algebra 6 October 29th, 2011 04:32 PM Gustav Algebra 11 February 28th, 2011 06:04 AM

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