July 18th, 2017, 05:22 AM  #41 
Senior Member Joined: Mar 2015 From: New Jersey Posts: 1,189 Thanks: 90 
Two binarydigit natural numbers: 00 > 0 01 > 1 10 > 2 11 > 3 Three binarydigit natural numbers: 000 > 0 001 > 1 010 > 2 011 > 3 100 > 4 101 > 5 110 > 6 111 > 7 Infinite binarydigit natural numbers (Infinite Binary Sequences): ....00000 > 0 ....00001 > 1 ....00010 > 2 ....00011 > 3 ....00100 > 4 ....00101 > 5 ....00110 > 6 ....00111 > 7 ............ ............ Preceding zeros conventionally not displayed or indicated. 
July 18th, 2017, 05:29 AM  #42  
Senior Member Joined: Oct 2009 Posts: 142 Thanks: 60  Quote:
And what would be ...111111 + 1?  
July 18th, 2017, 05:30 AM  #43  
Senior Member Joined: Oct 2009 Posts: 142 Thanks: 60  Quote:
 
July 18th, 2017, 08:59 AM  #44  
Senior Member Joined: Jun 2014 From: USA Posts: 316 Thanks: 22  Quote:
I realize you think that all of the infinite binary sequences appear in your list, as that is what you assert time and time again. You are flapping your arms as though you are convinced you can fly. Move on.  
July 18th, 2017, 09:55 AM  #45 
Global Moderator Joined: Dec 2006 Posts: 18,232 Thanks: 1437 
If you write the "infinite" sequences that way round, zylo, CDA is still applicable if you start the diagonal at the top right instead of the top left.

July 18th, 2017, 04:11 PM  #46 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,082 Thanks: 2360 Math Focus: Mainly analysis and algebra 
Since Zylo believes that his list goes $$\begin{gather}000\ldots000 \\ 000\ldots001 \\ 000\ldots010 \\ \vdots \\111\ldots111\end{gather}$$ This means that the first few have finite quantities of $1$s and the last few have infinite quantities of $1$s. A pertinent question is: when do we make the transition from finite $1$s to infinite $1$s?


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binary, blah, infinite, natural, number, sequence 
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