June 14th, 2017, 07:45 AM  #1 
Newbie Joined: Jun 2017 From: Yaoundecameroon Posts: 2 Thanks: 0  Functions.
We are given a function which is continuous, positive decreasing and integrable on [1,$\infty$[. We are required to show that as x tends to infinity, xf(x) tends to 0. How do we proceed?
Last edited by Micromike; June 14th, 2017 at 07:55 AM. Reason: An omission 
June 14th, 2017, 07:52 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 18,962 Thanks: 1606 
Consider what happens if it tends to a nonzero value.

June 15th, 2017, 05:07 PM  #3 
Global Moderator Joined: May 2007 Posts: 6,511 Thanks: 585 
Use fact integral of 1/x diverges as x becomes infinite.

June 16th, 2017, 03:26 AM  #4 
Newbie Joined: Jun 2017 From: Yaoundecameroon Posts: 2 Thanks: 0 
Where does the 1/x come from? Also as x tends to inf, 1/x tends to 0 Last edited by skipjack; June 17th, 2017 at 05:21 AM. 
June 17th, 2017, 03:45 AM  #5  
Math Team Joined: Jan 2015 From: Alabama Posts: 3,165 Thanks: 867  Quote:
"1/x" is sort of the "border" of "integrable functions". $\displaystyle \frac{1}{x^\alpha}$ is integrable, from 1 to infinity, as long as $\displaystyle \alpha> 1$. Last edited by skipjack; June 17th, 2017 at 05:21 AM.  

Tags 
functions 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Derivatives, trignometric functions and exponential functions  Nij  Calculus  2  November 25th, 2015 06:20 AM 
Help with Functions?  xKy  PreCalculus  2  April 21st, 2014 10:59 PM 
Functions  hoyy1kolko  Algebra  3  January 9th, 2011 12:28 PM 
Functions  Tartarus  Algebra  4  November 16th, 2009 01:36 AM 
help / functions  sel  Calculus  3  October 21st, 2008 03:48 AM 