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March 22nd, 2017, 06:30 AM   #1
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This question sounds silly, but I was just wondering since we are saying that the elements of the set are only for numbers greater than 0.

Last edited by skipjack; April 6th, 2017 at 12:16 AM.
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March 22nd, 2017, 08:00 AM   #2
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$a \in \mathbb R\ and\ 0 \le a \implies a + 1 \in \mathbb R\ and\ 0 \le a + 1.$

So there is no upper bound on that interval. There is of course a lower bound, namely zero.
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April 5th, 2017, 03:53 AM   #3
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And therefore, by the standard definition of "bounded", this set is not bounded.
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