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March 22nd, 2017, 06:30 AM  #1 
Member Joined: Jan 2016 From: Blackpool Posts: 40 Thanks: 0 
This question sounds silly, but I was just wondering since we are saying that the elements of the set are only for numbers greater than 0.
Last edited by skipjack; April 6th, 2017 at 12:16 AM. 
March 22nd, 2017, 08:00 AM  #2 
Senior Member Joined: May 2016 From: USA Posts: 632 Thanks: 257 
$a \in \mathbb R\ and\ 0 \le a \implies a + 1 \in \mathbb R\ and\ 0 \le a + 1.$ So there is no upper bound on that interval. There is of course a lower bound, namely zero. 
April 5th, 2017, 03:53 AM  #3 
Math Team Joined: Jan 2015 From: Alabama Posts: 2,492 Thanks: 632 
And therefore, by the standard definition of "bounded", this set is not bounded.


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