My Math Forum Sequences

 Real Analysis Real Analysis Math Forum

 December 1st, 2016, 12:49 PM #1 Member   Joined: Nov 2016 From: Kansas Posts: 70 Thanks: 0 Sequences So the question was of two parts of which I proved the first one. The second part goes as follows: ck= 2^k for k is even and ck= 1-1/k for which k is odd. I have to prove that lim ck=1. I know that these two are subsequences and can prove for ck= 1-1/k approaches 1 but how to prove for ck=2^k? It would be of great help if someone could show this or overall how to solve this part.
 December 1st, 2016, 01:39 PM #2 Global Moderator   Joined: May 2007 Posts: 6,497 Thanks: 580 $\displaystyle 2^k$ subsequence becomes infinite. There is something wrong with your statement of the problem.
December 3rd, 2016, 10:38 AM   #3
Math Team

Joined: Jan 2015
From: Alabama

Posts: 3,108
Thanks: 855

Quote:
 Originally Posted by ZMD So the question was of two parts of which I proved the first one. The second part goes as follows: ck= 2^k for k is even and ck= 1-1/k for which k is odd. I have to prove that lim ck=1. I know that these two are subsequences and can prove for ck= 1-1/k approaches 1 but how to prove for ck=2^k? It would be of great help if someone could show this or overall how to solve this part.
You don't! The statement you are trying to prove not true. The sequence defined does not converge at all.

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post ely_en Algebra 1 November 11th, 2011 01:07 PM sat Real Analysis 0 September 14th, 2011 07:50 AM remeday86 Number Theory 2 July 22nd, 2010 05:17 AM Kiranpreet Algebra 1 November 11th, 2008 02:48 PM cindyyo Algebra 2 August 20th, 2008 02:40 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top