October 29th, 2016, 03:50 PM  #1 
Member Joined: Oct 2016 From: New York Posts: 44 Thanks: 11 Math Focus: Analysis and Differential Geometry  Question about a proof
I am having difficulty understand why 0<=t<1. The proof says, "positive real numbers t such that.." Earlier (when it states the theorem) it also says x >0, so how is it possible that t is 0? Shouldn't it be 0<t<1? By the way this is my first time asking a question on here, so I don't know if my file got attached correctly. 
October 30th, 2016, 01:54 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,136 Thanks: 468 
You are correct, but it doesn't matter as far as the proof is concerned.

October 31st, 2016, 04:49 AM  #3 
Member Joined: Oct 2016 From: New York Posts: 44 Thanks: 11 Math Focus: Analysis and Differential Geometry 
Okay, thank you. I understand the proof still works. I just wanted clarification on that part.


Tags 
proof, question 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Proof Question  theengineer  Algebra  6  June 15th, 2016 10:19 AM 
Proof Question  Magnesium  Linear Algebra  1  December 27th, 2013 08:06 PM 
One proof question..!  eChung00  Number Theory  1  September 17th, 2012 03:44 PM 
Proof Question  julian21  Number Theory  1  November 27th, 2010 07:33 PM 
proof question  kindgirl  Algebra  13  October 28th, 2007 03:05 AM 