
Real Analysis Real Analysis Math Forum 
 LinkBack  Thread Tools  Display Modes 
January 29th, 2008, 08:15 PM  #1 
Newbie Joined: Jan 2008 Posts: 5 Thanks: 0  Geometric series/target of series/etc...
I need to: Find the target of the series: 1  (3/4) + (9/16)  (27/64) + ... + (1)^k*(3^k/4^k) Then i need to find any value of n so that any partial sum with at least n terms is within 0.001 of the target value. Justify the answer. So here's what I did. I made a program on Mathematica that gave me that the target value of the partial sum is .571429 (4/7) I also found that at the sum from 0 to the 22nd term is equivalent to 0.572193 I suppose I have my answer but I cannot justify it  except using proof by mathematica program. I am worried though that when I have an exam and am forced do this without mathematica I will not be able to. Is there any advice? Or can someone teach me how to do this? 
January 30th, 2008, 01:50 AM  #2  
Global Moderator Joined: Dec 2006 Posts: 18,140 Thanks: 1415  Quote:
so (3/4)S =  (3/4) + (9/16)  (27/64) + ... = S  1, and so S = 1/(1 + 3/4) = 4/7. You can find n such that (3/4)^n < 0.001. For example, n = 25. Can you see why such n has the property requested?  

Tags 
geometric, series or etc, series or target 
Search tags for this page 
Click on a term to search for related topics.

Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
geometric series  najaa  Algebra  4  February 1st, 2012 09:25 AM 
Geometric Series?  xela95  Algebra  5  June 17th, 2011 03:17 PM 
Convergent series > series of geometric means converges  The Chaz  Real Analysis  11  February 7th, 2011 05:52 AM 
Target Values & Series  mathjunkie  Real Analysis  1  September 25th, 2008 04:04 AM 
sequences and series: geometric series  cindyyo  Algebra  2  August 24th, 2008 02:25 AM 