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January 29th, 2008, 07:15 PM  #1 
Newbie Joined: Jan 2008 Posts: 5 Thanks: 0  Geometric series/target of series/etc...
I need to: Find the target of the series: 1  (3/4) + (9/16)  (27/64) + ... + (1)^k*(3^k/4^k) Then i need to find any value of n so that any partial sum with at least n terms is within 0.001 of the target value. Justify the answer. So here's what I did. I made a program on Mathematica that gave me that the target value of the partial sum is .571429 (4/7) I also found that at the sum from 0 to the 22nd term is equivalent to 0.572193 I suppose I have my answer but I cannot justify it  except using proof by mathematica program. I am worried though that when I have an exam and am forced do this without mathematica I will not be able to. Is there any advice? Or can someone teach me how to do this? 
January 30th, 2008, 12:50 AM  #2  
Global Moderator Joined: Dec 2006 Posts: 18,965 Thanks: 1606  Quote:
so (3/4)S =  (3/4) + (9/16)  (27/64) + ... = S  1, and so S = 1/(1 + 3/4) = 4/7. You can find n such that (3/4)^n < 0.001. For example, n = 25. Can you see why such n has the property requested?  

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