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December 6th, 2010, 07:25 AM  #1 
Newbie Joined: Dec 2010 Posts: 7 Thanks: 0  Proof of recurrence sequence convergence
Let be a recurrence sequecnce such that: (1) and are positive reals (2) For we have . Proof that is convergent. 
December 6th, 2010, 08:51 AM  #2 
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 937 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Re: Proof of recurrence sequence convergence
What happens when the sum is > 1? What happens when the sum is < 1?

December 6th, 2010, 01:20 PM  #3 
Newbie Joined: Dec 2010 Posts: 7 Thanks: 0  Re: Proof of recurrence sequence convergence
From such cases (if you are talking about denominator) follows estimation for the next element of our sequence and I dont see anything more. I tried to divide it into two subsequences such that 1st is composed of elements greater then one, and 2nd consists of numbers lesser then one. After that if 1st was nonincreasingand 2nd nondecreasing (actually it requiers their convergance only) with some easy calculus I can show that they have a common limit. My prove attempt distinguished eight cases (there cant be three elements in a row that belong into on of these subsequances) but some of them are troublesome or simply false (for example they may be monotonic only for enought big values). 

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