October 19th, 2010, 06:59 AM  #1 
Newbie Joined: Oct 2010 Posts: 3 Thanks: 0  Asymptotics
Hello. Here is the problem: . How to find where . I need your ideas Thanks 
October 19th, 2010, 08:38 AM  #2 
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Re: Asymptotics
Well, k! is about (k/e)^k, so 1/log(k) is about 1/(k log k  k). integral 1/k log k up to m is log log m, so that's a reasonable guess. Actually integral 1/(k log k  k) is log(log m  1) so that 'should be' even more accurate.


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