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November 28th, 2009, 10:38 PM  #1 
Newbie Joined: Nov 2009 Posts: 1 Thanks: 0  Help to create ranking formula!
I am a computer scientist and I want to create a ranking formula for an application, so I thought to post in a math forum instead of developers forums coz you are the gurus in topics like this! Basically I want to create a ranking formula where the rank number (result) will be between 01 inclusive. And the problem is: I have two variables, x and y, where x&y can take values between 19, inclusive. And I want a formula where I can manipulate these variables and get a result (e.g 0.765 or 0.453). The highest the better, so if both x and y take the max value (=9) then the number should be really close to 1 (e.g 0.928 or something or if not so close, to be the closet to 1 if x and y take the max value) I thought of this: 11/((x*y)^2) but when x= 9 y=9 result = 0.9998475... and when x=5 y=5 result= 0.9984 also when x= 1 y= 1 result= 0 so I don't think this is efficient and I am sure there must be a better formula than this. Any help or hints on how to design my formula ? 
November 29th, 2009, 08:29 AM  #2 
Member Joined: Oct 2009 Posts: 64 Thanks: 0  Re: Help to create ranking formula!
You want a number that is highest when x and y are equal and lowest when min(x,y) is substantially different from max(x,y), right? Try something like 1(xy)^2/(x+y)^2, I guess. 
November 29th, 2009, 10:59 AM  #3 
Senior Member Joined: Aug 2008 From: Blacksburg VA USA Posts: 338 Thanks: 4 Math Focus: primes of course  Re: Help to create ranking formula!
well, you give very minimal info so my minimal sol'n would be to just sum x&y, and offset/scale to put into desired ranging. So, if x,y range is 19, the range of the sum is 218. We offset by 2 and divide by 16 to give result=(x+y2)/16. It will then range 01, and peak when x&y both peak. A previous post thought maybe the result peaks when x=y but I did not interpret it this way. If so, post back and we can give it another go.


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