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March 30th, 2015, 03:07 AM  #1 
Newbie Joined: Mar 2015 From: Australia Posts: 2 Thanks: 0  help with rearranging formulas
Very simple issue but it's been nearly 20 years since I did transposition(or any serious maths at all! ) and I'm seriously struggling to get my head back around it. Just trying to understand how he has got to the answer in this example. x= accuracy = ±0.01 L = length of x axis within defined accuracy x = ±0.01 = L sin 0°00'4" L = 515 metres Hope it is filled out close enough, having trouble working out how to get mathematical symbols to display nicely on the screen too I think I am correct that 0°00'4" converts to 0.0011° (decimal degrees) but for the life of me I can't work out how he's got the length of 515m. Feeling very in over my head here 
March 30th, 2015, 04:28 AM  #2 
Newbie Joined: Mar 2015 From: Australia Posts: 2 Thanks: 0 
haha, well I worked it out. Pretty pleased with myself I thought but the next one makes even less sense to me y = ±0.01 = ±(0.005 + L x 5 x 10^6) I need to solve for L but not sure how to pull L out on it's own. Will say though that having managed to rearrange the other couple I'm starting to feel it coming back to me. 

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formulas, rearranging 
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