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March 23rd, 2015, 05:41 PM  #1 
Newbie Joined: Mar 2015 From: Chicago Posts: 22 Thanks: 1  Clarification on permutation of license plates?
The problem doesn't make any sense to me. Here it goes: How many different six digit license plates of the same state can have the digits 3,5,5,6,2 and 6? I don't even know where to start from the problem? Is it the number six divided by all the other numbers or the reverse of what I said? 
March 23rd, 2015, 06:01 PM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs 
There are $6!$ ways to permute the six digits, and $2!$ ways to permute each pair of repeat digits. So the number $N$ of plates is: $\displaystyle N=\frac{6!}{2!\cdot2!}=180$ 
March 24th, 2015, 05:36 PM  #3 
Newbie Joined: Mar 2015 From: Chicago Posts: 22 Thanks: 1 
Thank you MarkFL! I appreciate you taking your time to save the problem in order for me to understand! í ½í¸ƒ


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clarification, driver, license, licenses, permutation, plates 
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