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March 23rd, 2015, 05:41 PM   #1
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Clarification on permutation of license plates?

The problem doesn't make any sense to me. Here it goes:

How many different six digit license plates of the same state can have the digits 3,5,5,6,2 and 6?

I don't even know where to start from the problem? Is it the number six divided by all the other numbers or the reverse of what I said?
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March 23rd, 2015, 06:01 PM   #2
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There are $6!$ ways to permute the six digits, and $2!$ ways to permute each pair of repeat digits. So the number $N$ of plates is:

$\displaystyle N=\frac{6!}{2!\cdot2!}=180$
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March 24th, 2015, 05:36 PM   #3
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Thank you MarkFL! I appreciate you taking your time to save the problem in order for me to understand!
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