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January 4th, 2015, 11:31 AM  #1 
Newbie Joined: Jan 2015 From: Lithuania Posts: 6 Thanks: 0  Need help again...
Hello again, sorry for asking for too much, but I'm facing problems again... The task goes like this: There are 18 archers. 5 of them hit the target with the probability 0,8; 7 with the probability 0,7; 4 with the probability 0,6 and 2 with the probability 0,5. A randomly picked archer shot, but missed the target. What is the probability that he belonged to the group of archers who have the probability of 0,7 of hitting the target? THE CORRECT ANSWER IS 7/19. I thought it was 7/18, but I was wrong. Does someone know how to get the right answer? Thank you for the help! Last edited by skipjack; January 4th, 2015 at 01:12 PM. 
January 4th, 2015, 01:09 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,045 Thanks: 1618 
7*(1  0.7)/(5*(1  0.8) + 7*(1  0.7) + 4*(1  0.6) + 2*(1  0.5)) = 7/19

January 4th, 2015, 08:26 PM  #3 
Newbie Joined: Jan 2015 From: Lithuania Posts: 6 Thanks: 0 
Thank you very much!
