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December 23rd, 2014, 04:24 PM   #1
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Expected Value

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January 2nd, 2015, 08:56 AM   #2
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P(1 '1') = 1/6 * 5/6 * 2 = 5/18

P(2 '1's) = 1/6 * 1/6 = 1/36

P(No '1's) = 5/6 * 5/6 = 25/36

Thus expected value = 1 * 5/18 + 2 * 1/36 + 0 * 25/36 = 1/3.
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