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December 23rd, 2014, 04:24 PM   #1
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Expected Value

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 January 2nd, 2015, 08:56 AM #2 Senior Member   Joined: Dec 2012 From: Hong Kong Posts: 853 Thanks: 311 Math Focus: Stochastic processes, statistical inference, data mining, computational linguistics P(1 '1') = 1/6 * 5/6 * 2 = 5/18 P(2 '1's) = 1/6 * 1/6 = 1/36 P(No '1's) = 5/6 * 5/6 = 25/36 Thus expected value = 1 * 5/18 + 2 * 1/36 + 0 * 25/36 = 1/3.

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