Probability and Statistics Basic Probability and Statistics Math Forum

 May 14th, 2014, 11:43 AM #1 Newbie   Joined: May 2014 From: england Posts: 11 Thanks: 0 independent events rule question - please please help as exam tomorrow! For 2 independent events, A and B, p(AuB')=0.7 and P(A)=0.5. A and B are independent. Find the probability of event B happening.? I do not understand this question, sorry. The markscheme working is (0.3+x)0.5=x 0.15 = 0.5x x=0.3 p(B)=0.6 if this is the independent events rule, where does b being 0.3+x come from please? id really appreciate a step-by-step response thanks!
 May 14th, 2014, 12:52 PM #2 Global Moderator   Joined: May 2007 Posts: 6,807 Thanks: 717 I don't where the formula came from. My approach: P(A∪B') = P(A) + P(B') - P(A∩B') P(A∩B') = P(A)P(B') (independence) Let x = P(B') .7 = .5 + x - .5x x = .4 P(B) = 1-x = .6
 May 15th, 2014, 01:25 AM #3 Newbie   Joined: May 2014 From: england Posts: 11 Thanks: 0 thanks thanks a lot! understood

 Tags events, exam, independent, question, rule, tomorrow

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post Chriiisss Applied Math 0 April 21st, 2013 04:36 PM Keroro Algebra 1 June 6th, 2012 08:17 AM csoles Elementary Math 1 March 20th, 2012 08:03 PM kabal Calculus 2 May 22nd, 2010 05:37 PM Siria Advanced Statistics 4 July 5th, 2009 09:21 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top