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February 3rd, 2014, 08:37 AM  #1 
Newbie Joined: Feb 2014 Posts: 3 Thanks: 0  Probability! Help Needed!
I'm taking a probability class and this question was posed by my teacher. it seems simple but me and my friend have been stuck on it for a while. Can anyone help answer this question or at least pose a method to answering it for us? You are rushing to go away for the weekend and you randomly grab 4 shoes from 4 different pairs in your closet. What is the probability that you have at least one pair? 
February 3rd, 2014, 09:15 AM  #2 
Senior Member Joined: Nov 2013 From: Baku Posts: 502 Thanks: 56 Math Focus: Geometry  Re: Probability! Help Needed!
(1) FIrst fined total chances. C(16,4) (2) Then calculate One pair and nonpairs C(8,1)*C(14,1)*C(12,1) (3) Find chances for two pairs C(8,2) Answer is [(2) + (3)]/(1) 
February 3rd, 2014, 09:26 AM  #3 
Newbie Joined: Feb 2014 Posts: 3 Thanks: 0  Re: Probability! Help Needed!
but the answer has to be less than 1 if its the probability. we know the answer is roughly .77 or exactly 27/35, but we don't know how to get to that.

February 3rd, 2014, 12:46 PM  #4  
Global Moderator Joined: May 2007 Posts: 6,823 Thanks: 723  Re: Probability! Help Needed! Quote:
a  prob. that second shoe is match b  prob. that third shoe is match (second shoe not) c  prob. that fourth shoe is match (second and third not) match means match to any previously chosen.  
February 3rd, 2014, 01:39 PM  #5  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  Re: Probability! Help Needed! Hello, shcorina! Quote:
 
February 3rd, 2014, 05:02 PM  #6  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038  Re: Probability! Help Needed! Quote:
 

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