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 October 17th, 2013, 06:16 PM #1 Newbie   Joined: Oct 2013 Posts: 1 Thanks: 0 *Probability Problem - please help!* I need the answer/brief explanation for this question by tonight! Any replies would be greatly appreciated! In a particular game, a fair die is tossed. If the number rolled is either a four or five, you win $1. If the number rolled is a six, you win$4. If the number rolled is a one, two, or three, you win nothing. You are going to play the game twice. The probability that you win at least \$1 both times is (a) 1/2 (b) 4/36 (c) 1/36 (d) 1/4 (e) 3/4
 October 18th, 2013, 05:00 AM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,948 Thanks: 1140 Math Focus: Elementary mathematics and beyond Re: *Probability Problem - please help!* 1/2 * 1/2 = 1/4.

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