My Math Forum In a shooting test, probability of hitting the target

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 October 12th, 2013, 12:34 AM #1 Senior Member   Joined: Oct 2009 Posts: 895 Thanks: 1 In a shooting test, probability of hitting the target In a shooting test, the probability of hitting the target is 1/2 for A and 2/3 for B and 3/4 for C. Find the probability that 1 ) none of them hits the target 2 ) the target is hit 3 ) all of them will hit the target
 October 12th, 2013, 12:49 AM #2 Global Moderator   Joined: Dec 2006 Posts: 19,503 Thanks: 1740 I assume the events "A hits the target", "B hits the target" and "C hits the target" are independent. P(A misses the target) = 1 - 1/2 = 1/2. P(B misses the target) = 1 - 2/3 = 1/3. P(C misses the target) = 1 - 3/4 = 1/4. 1)  Hence the probability that A, B and C all miss the target is (1/2 )(1/3)(1/4) = 1/24. 2)  Hence the probability that the target is hit by at least one of A, B and C is 1 - 1/24 = 23/24. 3)  The probability that A, B and C all hit the target is (1/2)(2/3)(3/4) = 1/4.
 October 12th, 2013, 01:14 AM #3 Senior Member   Joined: Oct 2009 Posts: 895 Thanks: 1 Re: In a shooting test, probability of hitting the target thanks What is the thing you can ask here in question also ?

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