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October 12th, 2013, 01:34 AM   #1
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In a shooting test, probability of hitting the target

In a shooting test, the probability of hitting the target is 1/2 for A and 2/3 for B
and 3/4 for C. Find the probability that

1 ) none of them hits the target
2 ) the target is hit
3 ) all of them will hit the target
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October 12th, 2013, 01:49 AM   #2
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I assume the events "A hits the target", "B hits the target" and "C hits the target" are independent.
P(A misses the target) = 1 - 1/2 = 1/2.
P(B misses the target) = 1 - 2/3 = 1/3.
P(C misses the target) = 1 - 3/4 = 1/4.

1)  Hence the probability that A, B and C all miss the target is (1/2 )(1/3)(1/4) = 1/24.

2)  Hence the probability that the target is hit by at least one of A, B and C is 1 - 1/24 = 23/24.

3)  The probability that A, B and C all hit the target is (1/2)(2/3)(3/4) = 1/4.
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October 12th, 2013, 02:14 AM   #3
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Re: In a shooting test, probability of hitting the target

thanks

What is the thing you can ask here in question also ?
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