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October 12th, 2013, 12:18 AM   #1
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In building new home a contractor finds that the probability

In building new home a contractor finds that the probability of home buyer selecting a two-car garage is 0.70 and of selecting a one-car garage is 0.20 . Find the probability that the buyer will select no garage


[color=#004000] Please how we can now from this question if A and B are independent
and how we can know if here is mutuality exclusive or not [/color]
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October 12th, 2013, 04:13 AM   #2
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Re: In building new home a contractor finds that the probabi

Quote:
Find the probability that the buyer will select no garage
Very simple. p(no garage) = 1- p(one garage) - p(two garage) = 0.1. This is only true if we suppose (unlike your text) that 3 or more garage are not possible. If we don't know this fact, then there is no solution obviously.

Quote:
if A and B are independent
I reckon you meant by A and B that A = one garage and B = two garages. In that case your assumption doesn't make sense. Two (non-elementary) cases are independent if P(A and B) = P(A)*P(B). But two elementary cases never can be independent, because they are mutually exclusive, that is P(A and B) = P(impossible) = 0. If someone has exactly one garage then he can't have exactly two garages.
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October 12th, 2013, 04:39 AM   #3
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Re: In building new home a contractor finds that the probabi

thanks sou much
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