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June 14th, 2013, 07:33 AM  #1 
Newbie Joined: Jun 2013 Posts: 1 Thanks: 0  hard question of probability
At one school the probability of a student being a fan of Brazil is 0,6, to watch movies is 0,7 and enjoy the beach is 0,8. Between what values ??we find the probability of a student of this school simultaneously cheer for Brazil, watch the movie and enjoy the beach?

June 14th, 2013, 12:43 PM  #2  
Global Moderator Joined: May 2007 Posts: 6,136 Thanks: 468  Re: hard question of probability Quote:
Worst case Brazil fan include all nonwatch movie and nonenjoy beach. Also nonwatch movie all enjoy beach and all nonenjoy beach all watch movie. min = 0.6  0.3  0.2 = 0.1  

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