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May 13th, 2013, 03:04 PM   #1
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probability

If all $5 dollar bill contains eight non-zero digits, what is the probability that your bill contains the number 3 at least once?

I came up with 1-P(no 3) or 1-(8^9)/(9^ = approx .61206

does that seem right?
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May 13th, 2013, 03:53 PM   #2
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Re: probability

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May 13th, 2013, 06:30 PM   #3
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Re: probability

Quote:
Originally Posted by greg1313
yes?......
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May 13th, 2013, 06:43 PM   #4
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Re: probability

Do you have a question?
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May 14th, 2013, 09:54 PM   #5
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Re: probability

I think the answer is; 1-2(8/9)^8
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May 14th, 2013, 10:05 PM   #6
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Re: probability

Quote:
Originally Posted by fcheaito@hotmail.com
I think the answer is; 1-2(8/9)^8
This is incorrect, but why do you think this? What is your reasoning?
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May 15th, 2013, 08:17 AM   #7
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How many $5 dollar bills have been produced?
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