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May 13th, 2013, 03:04 PM  #1 
Member Joined: Mar 2012 Posts: 60 Thanks: 0  probability
If all $5 dollar bill contains eight nonzero digits, what is the probability that your bill contains the number 3 at least once? I came up with 1P(no 3) or 1(8^9)/(9^ = approx .61206 does that seem right? 
May 13th, 2013, 03:53 PM  #2 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,932 Thanks: 1127 Math Focus: Elementary mathematics and beyond  Re: probability 
May 13th, 2013, 06:30 PM  #3  
Member Joined: Mar 2012 Posts: 60 Thanks: 0  Re: probability Quote:
 
May 13th, 2013, 06:43 PM  #4 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,932 Thanks: 1127 Math Focus: Elementary mathematics and beyond  Re: probability
Do you have a question?

May 14th, 2013, 09:54 PM  #5 
Newbie Joined: May 2013 Posts: 4 Thanks: 0  Re: probability
I think the answer is; 12(8/9)^8

May 14th, 2013, 10:05 PM  #6  
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs  Re: probability Quote:
 
May 15th, 2013, 08:17 AM  #7 
Global Moderator Joined: Dec 2006 Posts: 20,480 Thanks: 2039 
How many $5 dollar bills have been produced?


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