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May 2nd, 2013, 09:15 PM   #1
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Probability

There are only two North American professional baseball teams that have never been to the championship series: the teams from Seattle and Washington D.C. (who never played for a championship when they were in Montreal, either). Before the season started the Seattle team had odds of 65-to-1 against them winning the championship. The Washington team was 9-to-1 against.

If these truly are the odds, what is the probability that one of these two teams will win the championship? (Must be in reduced fraction).
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May 3rd, 2013, 07:04 AM   #2
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Re: Probability

Let p be the probability that a given team wins and odds be defined as p/(1 - p). For Seattle: p/(1 - p) = 1/65, p = 1/66. For Washington: p/(1 - p) = 1/9, p = 1/10. Unless I'm mistaken in my interpretation of "odds", there is a 1/66 + 1/10 = 19/165 probability that one of the two teams will win the championship.
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