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 May 2nd, 2013, 09:15 PM #1 Newbie   Joined: Apr 2013 Posts: 6 Thanks: 0 Probability There are only two North American professional baseball teams that have never been to the championship series: the teams from Seattle and Washington D.C. (who never played for a championship when they were in Montreal, either). Before the season started the Seattle team had odds of 65-to-1 against them winning the championship. The Washington team was 9-to-1 against. If these truly are the odds, what is the probability that one of these two teams will win the championship? (Must be in reduced fraction).
 May 3rd, 2013, 07:04 AM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,929 Thanks: 1124 Math Focus: Elementary mathematics and beyond Re: Probability Let p be the probability that a given team wins and odds be defined as p/(1 - p). For Seattle: p/(1 - p) = 1/65, p = 1/66. For Washington: p/(1 - p) = 1/9, p = 1/10. Unless I'm mistaken in my interpretation of "odds", there is a 1/66 + 1/10 = 19/165 probability that one of the two teams will win the championship.

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