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May 2nd, 2013, 09:15 PM  #1 
Newbie Joined: Apr 2013 Posts: 6 Thanks: 0  Probability
There are only two North American professional baseball teams that have never been to the championship series: the teams from Seattle and Washington D.C. (who never played for a championship when they were in Montreal, either). Before the season started the Seattle team had odds of 65to1 against them winning the championship. The Washington team was 9to1 against. If these truly are the odds, what is the probability that one of these two teams will win the championship? (Must be in reduced fraction). 
May 3rd, 2013, 07:04 AM  #2 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,929 Thanks: 1124 Math Focus: Elementary mathematics and beyond  Re: Probability
Let p be the probability that a given team wins and odds be defined as p/(1  p). For Seattle: p/(1  p) = 1/65, p = 1/66. For Washington: p/(1  p) = 1/9, p = 1/10. Unless I'm mistaken in my interpretation of "odds", there is a 1/66 + 1/10 = 19/165 probability that one of the two teams will win the championship.


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