My Math Forum  

Go Back   My Math Forum > High School Math Forum > Probability and Statistics

Probability and Statistics Basic Probability and Statistics Math Forum

Thanks Tree1Thanks
  • 1 Post By mathman
LinkBack Thread Tools Display Modes
September 15th, 2019, 08:00 AM   #1
Joined: Sep 2019
From: New York

Posts: 3
Thanks: 0

Probability inequality problem

Suppose A and B are independent and identically distributed.
For the purposes of this problem, x and y are not capped at 1, but are definitely at least 0.


I know Pr(AUB)<x+y, but is it possible to make the right side any lower? What is the lowest it can be given the information above?
bluekaterpillar is offline  
September 15th, 2019, 01:51 PM   #2
Global Moderator
Joined: May 2007

Posts: 6,852
Thanks: 743

$Pr(A\cup B)=Pr(A)+Pr(B)-Pr(A\cap B)=Pr(A)+Pr(B)-Pr(A)Pr(B)$. You are now on your own.
mathman is offline  
September 16th, 2019, 07:29 AM   #3
Senior Member
Joined: Jun 2019
From: USA

Posts: 380
Thanks: 205

This is one of those, "It's so obvious once you see the solution," problems.
DarnItJimImAnEngineer is offline  

  My Math Forum > High School Math Forum > Probability and Statistics

inequality, probability, problem

Thread Tools
Display Modes

Similar Threads
Thread Thread Starter Forum Replies Last Post
Probability inequality laythtunopariso Advanced Statistics 1 May 17th, 2013 03:03 AM
Probability- Chebychevs Inequality MattyMath123 Advanced Statistics 1 April 12th, 2013 02:32 AM
Inequality problem Crouch Number Theory 6 January 1st, 2011 05:12 AM
Inequality Problem knowledgegain Algebra 1 May 6th, 2009 02:37 PM
Probability- Chebychevs Inequality MattyMath123 Algebra 0 December 31st, 1969 04:00 PM

Copyright © 2019 My Math Forum. All rights reserved.