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June 7th, 2019, 07:21 AM   #1
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Probability

This question is from my examination paper:

One bag contains 4 white and 3 black balls
and a second bag contains 3 white and
5 black balls. One ball is drawn from the
first bag and placed unseen in the second
bag. What is the probability that a ball now
drawn from the second bag is black ?

My final answer was 38/63.

Can someone please check that for me whether I answered it correctly or not?
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June 7th, 2019, 09:47 AM   #2
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$\dfrac 4 7\dfrac 5 9 + \dfrac 3 7 \dfrac 6 9 = \\

\dfrac{20}{63}+\dfrac{18}{63} = \dfrac{38}{63}$

well done
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June 7th, 2019, 10:29 AM   #3
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