My Math Forum Please tell me how to approach this problem on deer hunt
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 February 3rd, 2019, 07:38 AM #1 Newbie   Joined: Feb 2019 From: United states Posts: 8 Thanks: 0 Solve deer hunting probability A hunter knows that a deer is hidden in one of the two near by bushes, the probability of its being hidden in bush-I being 4/5. The hunter having a rifle containing 10 bullets decides to fire them all at bush-I or II. It is known that each shot may hit one of the two bushes, independently of the other with probability 1/2. Number of bullets must he fire on bush-I to hit the animal with maximum probability is ________. (Assume that the bullet hitting the bush also hits the animal). Please help me as how to approach this problem. Last edited by skipjack; February 4th, 2019 at 04:35 AM.
 February 3rd, 2019, 09:15 AM #2 Senior Member   Joined: May 2016 From: USA Posts: 1,306 Thanks: 549 I suggest that you copy the problem exactly as it is written. if it makes no difference which bush he aims at, the problem does not seem to make much sense.
 February 3rd, 2019, 09:28 AM #3 Newbie   Joined: Feb 2019 From: United states Posts: 8 Thanks: 0 I have posted as it is. I can give you the link also if you want.
February 3rd, 2019, 10:02 AM   #4
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 Originally Posted by Jayant98 I have posted as it is. I can give you the link also if you want.
Well I am not too sure I want to galivant off to some unknown site. It says that you are in the US. Why are you using a site that has such terrible English, or is it written in some other language that you have translated from?

February 3rd, 2019, 11:44 AM   #5
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 Originally Posted by JeffM1 Well I am not too sure I want to galivant off to some unknown site. It says that you are in the US. Why are you using a site that has such terrible English, or is it written in some other language that you have translated from?
What can I say to this? I had downloaded this assignment so as to practice the questions from Probabs and then I got this.

 February 3rd, 2019, 01:24 PM #6 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,978 Thanks: 994 Home, home on the range, Where the deer and the antelope play
February 3rd, 2019, 06:30 PM   #7
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 Originally Posted by Jayant98 What can I say to this? I had downloaded this assignment so as to practice the questions from Probabs and then I got this.
I am sorry. We DO like to help. But we must understand the question before we can give sensible help.

What is PROBABS? I was not able to find a probabs.com, probab.com,
probabs.edu, probab.edu, probabs.edu, or a probab.org. This did not increase my desire to visit the site.

Given that your question seems to have been written by someone who barely knows English, perhaps there is a more reliable site to use. (I am fully aware that knowledge of English is not a prerequisite to being a great mathematician, but knowledge of English is a prerequisite to asking intelligible questions and giving intelligible explanations in English.)

Have you looked at Khan Academy for example?

 February 3rd, 2019, 10:39 PM #8 Senior Member     Joined: Sep 2015 From: USA Posts: 2,314 Thanks: 1230 I think I understand what the problem is trying to say. You've got 10 arrows. You're going to shoot all 10. $n$ at bush 1 and $10-n$ at bush 2 $P_{kill}(n) = \dfrac{4}{5}\left(1-\left(\dfrac 1 2\right)^n\right) + \dfrac{1}{5}\left(1-\left(\dfrac 1 2\right)^{10-n}\right)$ You can maximize this the usual way via the first derivative, or as there are only 11 values you can just list them and find the maximum by inspection. It's seen that $p_{kill}(6) = 0.975$ is the maximum Thanks from JeffM1 and Jayant98
 February 4th, 2019, 04:32 AM #9 Global Moderator   Joined: Dec 2006 Posts: 20,298 Thanks: 1971 A web search finds this problem on various web sites, with much the same poor English on all of them. Thanks from Jayant98
February 7th, 2019, 03:38 AM   #10
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 Originally Posted by romsek I think I understand what the problem is trying to say. You've got 10 arrows. You're going to shoot all 10. $n$ at bush 1 and $10-n$ at bush 2 $P_{kill}(n) = \dfrac{4}{5}\left(1-\left(\dfrac 1 2\right)^n\right) + \dfrac{1}{5}\left(1-\left(\dfrac 1 2\right)^{10-n}\right)$ You can maximize this the usual way via the first derivative, or as there are only 11 values you can just list them and find the maximum by inspection. It's seen that $p_{kill}(6) = 0.975$ is the maximum
Why did you do (1-(0.5)^n)? Shouldn't it be (0.5)^n only for getting the 1st bush shot perfectly? And similarly for second bush also.

Last edited by Jayant98; February 7th, 2019 at 03:39 AM. Reason: Added more details

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