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December 22nd, 2018, 10:29 AM  #1 
Member Joined: Apr 2017 From: India Posts: 39 Thanks: 0  Probability and statistics
If 3 books are selected at random from a shelf containing 5 Novels, 3 Books of poems and a dictionary, what is the probability that a) dictionary is not selected b) 2 Novels and 1 Book of poems are selected I tried doing it, however I am unable to guess what will go in the denominator part of the answer. Can someone please help me solve this question? 
December 22nd, 2018, 10:47 AM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,264 Thanks: 1198 
of the 9 books only 1 is a dictionary so P[not selecting dictionary] = 8/9 there are 5 novels from the 9, we select one, now there are 4 novels of 8 and we select another one, now there are 3 poems of 7, and we select one. P[2 novels and 1 poems] = 5/9 4/8 3/7 = 60/504 
December 23rd, 2018, 11:40 AM  #3  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,801 Thanks: 970  Quote:
3 poems from the 9: 3/9 4 novels from the 8: 4/8 5 novels from the 7: 5/7 3/9 * 4/8 * 5/7 = 60/504 = 5/52 Thanks Romsek: yo my probability teacher!!  

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