My Math Forum Tricky Probability question

 Probability and Statistics Basic Probability and Statistics Math Forum

 October 25th, 2018, 05:44 PM #1 Newbie   Joined: Oct 2018 From: Lake Worth, FL Posts: 1 Thanks: 0 HELP PLEASE! Been on this for days! There are 17 questions in an quiz with each question having 3 choices(AB&C) but only 1 of the choices is the correct answer. Additionally, In 7 out of the 17 questions, you have the choice of selecting 2 choices (such as A&B or A&C or C&B) if you are not sure of your answer in these questions. Come up with a combination of answers that ensure that you cover all probabilities and get the correct combination of answers. What I mean is, You can do the quiz in more than 1 leaflet (Answering all questions) You can have 10 Leaflets or even 20! but at the END OF THE DAY, ONE LEAFLET OF ANSWERS MUST CONTAIN THE CORRECT ANSWER! Last edited by Young001; October 25th, 2018 at 05:57 PM.
 October 25th, 2018, 06:21 PM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,324 Thanks: 1233 10 of the 17 problems need 3 answers each to cover all the possible answers. This is equivalent to a 10 digit base 3 number and thus there are $3^{10} = 59049$ different answer sets to cover all the possibilities. The remaining 7 questions can be covered by 2 answers each and thus there are $2^7 = 128$ answer sets that cover the possibilities of these 7 questions. Multiplying these we have a total of $59049 \cdot 128 = 7558272$ different leaflets

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