My Math Forum Calculating overall percentage/probability from multiple categories?

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 August 9th, 2018, 12:26 PM #1 Newbie   Joined: Aug 2018 From: Finland Posts: 1 Thanks: 0 Calculating overall percentage/probability from multiple categories? Greetings, My apologies if the title is confusing; I don't really know how to explain what I am trying to do or what label this problem would fall under. Scenario: We have a magic bag, and inside the magic bag are an unknown/unlimited amount of coins. There are 100 different types of coins, but we are only interested in the iron, bronze, silver and gold coins, so we have bundled the other 96 types together as "other". We performed an experiment by taking one coin at a time from the magic bag and recording what type of coin it was; the coins we took from the magic bag were not placed back into the magic bag. We performed the experiment 1,000,000 times and the results are as follows: Other coins: 998,859 Iron coins: 596 Bronze coins: 312 Silver coins: 135 Gold coins: 98 First Question: Is it correct to say the probability to receive each coin from the magic bag is as follows? Other coins: (998,859/1,000,000)*100 = 99.8859% or 1,000,000/998,859 = 1 in 1.0011423 Iron coins: (596/1,000,000)*100 = 0.0596% or 1,000,000/596 = 1 in 1,678 Bronze coins: (312/1,000,000)*100 = 0.0312% or 1,000,000/312 = 1 in 3,205 Silver coins: (135/1,000,000)*100 = 0.0135% or 1,000,000/135 = 1 in 7,407 Gold coins: (98/1,000,000)*100 = 0.0098% or 1,000,000/98 = 1 in 10,204 Second Question: If I take only one coin from the magic bag, what is the chance/probability to receive either an iron, bronze, silver or gold coin? (Receiving any of these four coins would be a success, and receiving any of the other 96 coins would be a failure). I have tried to do some calculations, but I don't think I am working it out properly. - Is the following correct? ((0.0596/100)+(0.0312/100)+(0.0135/100)+(0.0098/100))*100 = 0.1141% (or 100% - 99.8859% = 0.1141%) - Is the following correct? ((1/1678)+(1/3205)+(1/7407)+(1/10204))*100 = 0.1141% - Is the following correct? (((1/1678)+(1/3205)+(1/7407)+(1/10204))/4)*100 = 0.0285% Third Question: If I take 1,400 coins from the magic bag, what is the chance/probability to receive either an iron, bronze, silver or gold coin? (Receiving any of these four coins would be a success, and receiving any of the other 96 coins would be a failure). I really have no idea how to calculate this; all I have managed to do is repeat one of the formulas above and multiply by 1,400. - Is the following correct? ((((1/1678)+(1/3205)+(1/7407)+(1/10204))/4)*100)*1400 = 39.9339% Fourth Question: What is the name for this type of probability? I understand that I am probably completely wrong about everything, so thank you very much to anyone willing to provide assistance.

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