My Math Forum Probability Applied To Poker

 Probability and Statistics Basic Probability and Statistics Math Forum

 August 5th, 2018, 08:29 PM #1 Newbie   Joined: Aug 2018 From: USA Posts: 1 Thanks: 0 Probability Applied To Poker I apply probability theory to Texas Hold Em Poker for fun, but I found a problem that has me stumped. I'm not sure exactly what is the correct way to solve this: In a game of Texas Hold Em Poker, you know that you've won...unless one (or more) of your opponents were dealt one (or more) of the 9 specific cards that can beat you. Of the 52 cards in a deck, only 45 remain unseen (2 were dealt to you faceup, 5 were dealt to the board faceup, 6 were dealt unseen to your opponents). None of the faceup cards are the 9 cards that can beat you. What is the probability that 1 (or more) of the 6 opponent's cards are 1 (or more) of the 9 specific cards needed to beat you? This is either a really easy problem that I'm overthinking, or one that is beyond my current understanding. Any guidance would be appreciated. Thanks!
 August 5th, 2018, 10:32 PM #2 Global Moderator   Joined: Dec 2006 Posts: 19,712 Thanks: 1805 Calculate the probability that the 39 cards remaining in the deck include all of the 9 specific cards, then subtract that probability from 1.

 Tags applied, poker, probability

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post Chemist@ Probability and Statistics 2 February 20th, 2016 02:51 PM WhiteLabel Probability and Statistics 4 January 25th, 2014 11:21 AM boyka Advanced Statistics 0 May 21st, 2013 07:00 AM Rudi Advanced Statistics 2 April 5th, 2011 05:54 AM MordorFires Advanced Statistics 1 October 21st, 2008 08:11 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top