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June 2nd, 2018, 02:32 PM  #1 
Senior Member Joined: Jan 2017 From: Toronto Posts: 178 Thanks: 2  interesting probability question
Newly borned babies with probability of 0.51 are boys, girls with probability of 0.49 and gender is independent across births. You meet a couple who tell you they have two children, and you ask whether they have any daughers. If they do (i.e. they have one or two girls), what is the probability that both of their children are girls? Hints: The probability of two girls is 0.49^2, but what I am looking for here is the probability of two girls conditional on having at least one girl (i.e. not having two boys). Since the probability of having two boys is 0.51^2, the probability of at least one girl is 1  0.51^2. Can you combine these pieces of information to get the correct answer? I am confused.. What exactly is the question asking for?? I thought the answer should have been 1  0.51^2 Last edited by zollen; June 2nd, 2018 at 03:32 PM. 
June 2nd, 2018, 03:58 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 1,980 Thanks: 1027 
$P[\text{both children are girls  they have two children and at least one daughter}]P[\text{they have two children and at least one daughter}] = P[\text{they have two children and at least one daughter  they have two daughers}]P[\text{they have two daughers}]$ $P[\text{they have two childeren and at least one daughterthey have two daughers}] = 1$ $P[\text{they have two daughters}] = (0.49)^2 = 0.2401$ $P[\text{they have two children and at least one daughter}] = \dbinom{2}{1}(0.49)(0.51) + \dbinom{2}{2}(0.49)^2 = 0.7399$ $P[\text{both children are girls  they have two children and at least one daughter}] = \dfrac{0.2401}{0.7399} \approx 0.3245$ 
June 3rd, 2018, 10:01 AM  #3 
Senior Member Joined: Jan 2017 From: Toronto Posts: 178 Thanks: 2  
June 3rd, 2018, 10:42 AM  #4 
Senior Member Joined: Sep 2015 From: USA Posts: 1,980 Thanks: 1027  
June 3rd, 2018, 11:02 AM  #5 
Senior Member Joined: Jan 2017 From: Toronto Posts: 178 Thanks: 2 
It mades more sense now.

June 3rd, 2018, 11:06 AM  #6 
Senior Member Joined: Sep 2015 From: USA Posts: 1,980 Thanks: 1027  

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