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 May 30th, 2018, 04:07 PM #1 Newbie   Joined: May 2018 From: south carolina Posts: 1 Thanks: 0 Homework help At a local college, 369 of the male students are smokers and 531 are non-smokers. Of the female students, 178 are smokers and 712 are non-smokers. A male student and a female student from the college are randomly selected for a survey. What is the probability that both are smokers? Do not round your answer
 May 30th, 2018, 04:25 PM #2 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,609 Thanks: 550 Math Focus: Yet to find out. Care to share your working?
 May 30th, 2018, 04:28 PM #3 Senior Member     Joined: Sep 2015 From: USA Posts: 2,037 Thanks: 1063 Because they are two separate populations and we are told we sample one of each the event of a male being a smoker or not is independent of that of a female being a smoker or not. Thus $P[\text{male and female samples are both smokers}]=P[\text{male sample is a smoker}]P[\text{female sample is a smoker}]$ You should be able to compute the right hand probabilities easy enough.
May 31st, 2018, 03:05 AM   #4
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Quote:
 Originally Posted by shanetha At a local college, 369 of the male students are smokers and 531 are non-smokers.
So there are a total of 900 male students, 531 of whom are non-smokers. What is the probability a randomly chosen male student is a smoker?

Quote:
 Of the female students, 178 are smokers and 712 are non-smokers.
So there are a total of 890 female students, 712 of whom are non-smokers. What is the probability a randomly chosen female student is a smoker?

Quote:
 A male student and a female student from the college are randomly selected for a survey. What is the probability that both are smokers? Do not round your answer
What romsek said.

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