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May 30th, 2018, 05:07 PM   #1
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Homework help

At a local college, 369 of the male students are smokers and 531 are non-smokers. Of the female students, 178 are smokers and 712 are non-smokers. A male student and a female student from the college are randomly selected for a survey. What is the probability that both are smokers? Do not round your answer
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May 30th, 2018, 05:25 PM   #2
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Math Focus: Yet to find out.
Care to share your working?
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May 30th, 2018, 05:28 PM   #3
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Because they are two separate populations and we are told we sample one of each the event of a male being a smoker or not is independent of that of a female being a smoker or not. Thus

$P[\text{male and female samples are both smokers}]=P[\text{male sample is a smoker}]P[\text{female sample is a smoker}]$

You should be able to compute the right hand probabilities easy enough.
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May 31st, 2018, 04:05 AM   #4
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Quote:
Originally Posted by shanetha View Post
At a local college, 369 of the male students are smokers and 531 are non-smokers.
So there are a total of 900 male students, 531 of whom are non-smokers. What is the probability a randomly chosen male student is a smoker?

Quote:
Of the female students, 178 are smokers and 712 are non-smokers.
So there are a total of 890 female students, 712 of whom are non-smokers. What is the probability a randomly chosen female student is a smoker?

Quote:
A male student and a female student from the college are randomly selected for a survey. What is the probability that both are smokers? Do not round your answer
What romsek said.
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