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 May 24th, 2018, 12:35 PM #1 Newbie   Joined: May 2018 From: Calgary, AB Posts: 5 Thanks: 0 More stats problems that make me cry Please don't ask me why my prof chose the most surfer-dude-esque names ever... Two buddies, Zeke and Bubba, plan a squirrel-hunting trip. Bubba is a better shot than Zeke. How much better? Bubba is 2-times a better shot than Zeke. Upon seeing a squirrel, Bubba and Zeke raise their rifles and simultaneously shoot at the squirrel. Assume that Bubba shooting the squirrel and Zeke shooting the squirrel are independent events, and that the probability of Zeke shooting the squirrel is 0.24. Part (a) What is the probability that the squirrel will be shot? P(squirrelshot)= (use four decimals) Part (b) What is the probability that both Zeke and Bubba will miss the squirrel? P(bothmiss)= (use four decimals) Part (c) If the squirrel is shot, what is the probability that Zeke shot the squirrel? P(Zekeshotthesquirrel)= (use four decimals) Part (d) If only one of the two buddies shot the squirrel, what is the probability it was Bubba? (use four decimals)
May 28th, 2018, 02:02 AM   #2
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Quote:
 Originally Posted by shetin Please don't ask me why my prof chose the most surfer-dude-esque names ever... Two buddies, Zeke and Bubba, plan a squirrel-hunting trip. Bubba is a better shot than Zeke. How much better? Bubba is 2-times a better shot than Zeke. Upon seeing a squirrel, Bubba and Zeke raise their rifles and simultaneously shoot at the squirrel. Assume that Bubba shooting the squirrel and Zeke shooting the squirrel are independent events, and that the probability of Zeke shooting the squirrel is 0.24.
Since "Bubba is 2-times a better shot than Zeke", the probability of Bubba shooting the squirrel is 0.48.

Quote:
 Part (a) What is the probability that the squirrel will be shot? P(squirrelshot)= (use four decimals)
Since "Bubba shooting the squirrel and Zeke shooting the squirrel are independent events" the probability that both Bubba and Zeke shoot the squirrel is 0.24(0.48 )= 0.1152. The probability the squirrel will be shot by either Bubba are Zeke or both is 0.24+ 0.48- 0.1152= 0.6048.

Quote:
 Part (b) What is the probability that both Zeke and Bubba will miss the squirrel? P(bothmiss)= (use four decimals)
1- 0.6048= 0.3952.

Quote:
 Part (c) If the squirrel is shot, what is the probability that Zeke shot the squirrel? P(Zekeshotthesquirrel)= (use four decimals)
Imagine this scenario happening 10000 times. The squirrel is shot 10000(0.6048 )= 6048 times. Of those, Zeke shot the squirrel 1000(0.24)= 240 times. Given that the squirrel is shot, the probability that Zeke shot it is 240/6048= 0.0397.

Quote:
 Part (d) If only one of the two buddies shot the squirrel, what is the probability it was Bubba? (use four decimals)
Of the 6048 times the squirrel is shot, it was shot, as above, byboth Zeke and Bubba 10000(0.1152)= 1152 times so it was shot by only one of them 6048- 1152= 4896 times. Of those times, Bubba shot the squirrel 4800- 1152= 3648 times. Given that only one of them shot the squirrel, the probability it was Bubba is 3648/4896= 0.7451.

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