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May 4th, 2018, 02:12 AM   #1
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probability problem

a Dice is thriwn $31$ times. Then probability of getting $2,4$ and $5$ at most $15$ times, is
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May 4th, 2018, 05:26 AM   #2
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Quote:
Originally Posted by panky View Post
Then probability of getting $2,4$ and $5$ at most $15$ times, is
You mean 2 or 4 or 5, right?

Same as getting 1 or 3 or 6 at most 16 times
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May 4th, 2018, 09:22 AM   #3
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$\sum \limits_{k=0}^{15}~\dbinom{31}{k}\left(\dfrac 1 2\right)^{31} = \dfrac 1 2$
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