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- - **How many codes can we create?**
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How many codes can we create? |

I'll take a stab at this. 3 places for the dot, $\displaystyle \binom{26}{2}$ ways to choose two letters, $\displaystyle \binom{10}{2}$ ways to choose two numbers, and 4! ways to line them up gives all ways allowing a zero at the start. So now we subtract out all those with zero at the start. Again, 3 places for the dot, $\displaystyle \binom{26}{2}$ ways to choose two letters, 9 ways to choose a digit, and 3! ways to line them up. So, $\displaystyle 3 \cdot \binom{26}{2}\binom{10}{2} \cdot 4! - 3 \cdot \binom{26}{2}\binom{9}{1} \cdot 3! = 100350$ |

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