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February 10th, 2018, 04:42 PM   #1
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Pack of cards with no replacement help

Answer requires justification:

A sequence of 3 cards is drawn from a standard deck of cards (with no replacement).

(a) How many of such sequences will have at least one king?
(b) How many of such sequences will have at least one king or one queen (or both)?
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February 11th, 2018, 02:40 PM   #2
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The probability of getting none of the desired cards is $\frac{(52-n)(51-n)(50-n)}{52\times 51\times 50}$. What you want is 1- this result. kings - n=4, kings or queens - n=8.
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