My Math Forum Pack of cards with no replacement help

 Probability and Statistics Basic Probability and Statistics Math Forum

 February 10th, 2018, 03:42 PM #1 Newbie   Joined: Oct 2017 From: Rumba Posts: 20 Thanks: 0 Pack of cards with no replacement help Answer requires justification: A sequence of 3 cards is drawn from a standard deck of cards (with no replacement). (a) How many of such sequences will have at least one king? (b) How many of such sequences will have at least one king or one queen (or both)?
 February 11th, 2018, 01:40 PM #2 Global Moderator   Joined: May 2007 Posts: 6,586 Thanks: 612 The probability of getting none of the desired cards is $\frac{(52-n)(51-n)(50-n)}{52\times 51\times 50}$. What you want is 1- this result. kings - n=4, kings or queens - n=8.

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