My Math Forum P(aub)=?

 Probability and Statistics Basic Probability and Statistics Math Forum

 October 15th, 2017, 06:47 PM #1 Newbie   Joined: Oct 2017 From: UK Posts: 1 Thanks: 0 P(aub)=? if P(A∩B)=0.04, P(A∩(1-P(B)))=0.38 how do you calculate P(A) = ?
 October 15th, 2017, 07:01 PM #2 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,643 Thanks: 571 Math Focus: Yet to find out. What have you tried? It might help to draw a diagram showing the intersection of A and B, and the compliment of B. Then try to form an expression for P(A).
 October 16th, 2017, 01:14 PM #3 Global Moderator   Joined: May 2007 Posts: 6,586 Thanks: 612 P(A∩(1-P(B))) doesn't look right. Did you mean P(A∩B')?
October 23rd, 2017, 11:02 AM   #4
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Quote:
 Originally Posted by bilguunee if P(A∩B)=0.04, P(A∩(1-P(B)))=0.38 how do you calculate P(A) = ?
I have no idea what "P(A∩(1-P(B)))" means! A is an event but 1- P(B) is a number the probability that even B does not happen. How do you intersect an event (a set) with a number?

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