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February 24th, 2013, 10:47 AM  #1 
Senior Member Joined: Jul 2011 Posts: 245 Thanks: 0  Probability and Arrangements
I figure that 1. is 13/16 (I did a tree diagram), and I figure that 2. is 3 (I wrote it all out). My questions are:

February 24th, 2013, 11:06 AM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs  Re: Probability and Arrangements
1.) I would look at the number of way for the Allens to have 5 or 4 girls. There is 1 way to have 5 girls, and 5 ways to have 4 girls, for a total of 6. Since there are 32 outcomes, then the number of ways to have at least 2 boys is: 
February 24th, 2013, 11:12 AM  #3  
Senior Member Joined: Jul 2011 Posts: 245 Thanks: 0  Re: Probability and Arrangements Quote:
 
February 24th, 2013, 11:46 AM  #4  
Math Team Joined: Apr 2012 Posts: 1,579 Thanks: 22  Re: Probability and Arrangements Quote:
 
February 24th, 2013, 04:02 PM  #5  
Senior Member Joined: Feb 2010 Posts: 711 Thanks: 147  Re: Probability and Arrangements Quote:
CAT CTA ACT For each of these there are two places to insert the geometry book. Thus 3 x 2 = 6. Here they are: CGAT CAGT CGTA CTGA AGCT ACGT  

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