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September 2nd, 2017, 12:43 PM   #1
Joined: Sep 2017
From: Oxford

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Probability re Placebo

Any help appreciated to calculate the below.

A clinical trial has two arms.

Arm 1 is placebo. The results generated were 17 responders out of 44 patients (38.6%)

Arm 2 is the active trial. The results generated were 49 responders out of 90 patients (54.4%)

How do I calculate the p number to show the likelihood of the active arm obtaining that statistical result by chance, i.e. the chance of there being no real difference between the active arm and placebo?

Anything under p=0.05 will be statistically significant, which is what I am trying to assess.

Thanks in advance

Last edited by siciliankan; September 2nd, 2017 at 12:44 PM. Reason: Extra information
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September 10th, 2017, 04:17 AM   #2
Joined: May 2013

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so lets create the probability square.
                                 prob(react to placebo) | prob(not react to placebo) |
 prob(react to actual)                                  |                                      |49/90
prob(not react to actual)                              |                                      |41/90
                                       17/44                  |  27/44                            | 1
we're looking for the upper left, the probability of reacting to placebo, and actual, which is simply 17/44*49/90 = 833/3960 =0.21 approx.
phillip1882 is offline  

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