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August 19th, 2017, 06:12 AM   #1
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Ice-cream problem

Hello buddies,
I am in big struggle to solve the following mathematical problem. I will try to translate it in English the best I can. (I will make additional corrections or explanation upon the translation, if that is required in order to make everything clear). Here I go:

We have 5 types of ice-cream: vanilla, banana, coconut, chocolate, forest fruits. And we have 4 types of syrup: strawberry, raspberry, blueberry, caramel. A person buys a portion of ice-cream (we have random choice here!) . The portion contains three different types of ice-cream and two different types of syrup.
What is the probability (in percents) of portion containing banana ice-cream and caramel syrup?

Please, help me, my head hurts. A clear, step-by-step solution and remark of the applied formulas will be very appreciated......
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August 19th, 2017, 06:19 AM   #2
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Math Focus: सामान्य गणित
For ice-cream, he can choose 3 different type out of 5. So there is 3/5 probability of containing banana ice-cream.

For syrup, he can choose 2 different type out of 4. So there is 2/4 probability of containing caramel syrup.

Hence, the probability of containing banana ice-cream and caramel syrup is

$\displaystyle \frac {3}{5} × \frac{2}{4} =30\% $
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August 19th, 2017, 06:26 AM   #3
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Quote:
Originally Posted by MATHEMATICIAN View Post
For ice-cream, he can choose 3 different type out of 5. So there is 3/5 probability of containing banana ice-cream.

For syrup, he can choose 2 different type out of 4. So there is 2/4 probability of containing caramel syrup.

Hence, the probability of containing banana ice-cream and caramel syrup is

$\displaystyle \frac {3}{5} × \frac{2}{4} =30\% $
thank you so much for the quick reply!
But i am so confused now...
In the textbook I have the answer, but not the solution. The answer in my textbook is: 15 %.
You say: 30 %

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