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February 21st, 2013, 08:29 AM  #1 
Newbie Joined: Feb 2013 Posts: 1 Thanks: 0  Continuous Probability?
Person A chooses a random real number a from 0 to 2. Person B choses a random real number b from 0 to 2. What is the probability that  a  b  > 1/3 In words: What is the probability that the absolute value of the difference is higher than 1/3?  I am not exactly sure how to get the final answer... I tried to define a random variable Z to be Z = X  Y, where X and Y are random variables that denote the chosen real numbers. I had E_z denote the event that Z > 1/3 (first considered the converse, that Z \leq 1/3). I'm actually not a fan of the absolute value sign, so I thought it would be easier to consider the event that X  Y > 1/3 OR X  Y < 1/3. I felt I was on the right path, but to no avail! Any help? 
February 21st, 2013, 09:02 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,633 Thanks: 2080 
See this topic, where a method of solution has been given.


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continuous, probability 
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