My Math Forum Bags problem

 Probability and Statistics Basic Probability and Statistics Math Forum

 May 19th, 2017, 12:38 AM #1 Newbie   Joined: May 2017 From: sweden Posts: 1 Thanks: 0 Bags problem You have 2 bags, A and B In bag A there's 3 white balls and 2 black balls In bag B there's 1 white balls and 3 black balls If you take only one ball from each bag, what is the probability that you will get one white ball and one black ball? Remember that there are two different combinations: A:3/5 and 3/4 = 45% B:1/4 and 2/5 = 10% Is the answer the average of 45 and 10 or are you supposed to just add them up?
 May 19th, 2017, 04:06 AM #2 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 9,425 Thanks: 640 b,w : 2/5 * 1/4 = 2/20 w,b : 3/5 * 3/4 = 9/20 add 'em: 11/20 multiply 'em: 18/400 = 9/200 SO?
 May 19th, 2017, 04:03 PM #3 Senior Member     Joined: Sep 2015 From: CA Posts: 1,238 Thanks: 637 to be formal it's $p = \dfrac{\dbinom{3}{1}}{\dbinom{5}{1}} \dfrac{\dbinom{3}{1}}{\dbinom{4}{1}}+\dfrac{ \dbinom{1}{1}}{\dbinom{4}{1}} \dfrac{\dbinom{2}{1}}{\dbinom{5}{1}}=\dfrac{11}{20 }$
 May 19th, 2017, 05:13 PM #4 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,170 Thanks: 383 Math Focus: Yet to find out. Bags bags bags.. they're very useful things..

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