
Probability and Statistics Basic Probability and Statistics Math Forum 
 LinkBack  Thread Tools  Display Modes 
March 9th, 2017, 03:54 AM  #1 
Newbie Joined: Mar 2017 From: South Africa Posts: 2 Thanks: 0  Probability Distributions
A wheat miller will only accept a consignment of wheat if the wheat has dried out completely. From past experience, the miller knows that approximately 15% of all wheat bags delivered is too wet to be processed immediately. If a random sample of 6 bags are drawn from each consignment he receives, find the probability that: 2.1.1. Exactly 3 bags being too wet 2.1.2. Less than 4 bags being too wet 2.1.3. At least 5 bags being too wet 2.1.4. Exactly 2 bags being dry enough Any help is greatly appreciated! i don't know how use these questions in the formula.. 
March 9th, 2017, 04:12 AM  #2  
Member Joined: Oct 2016 From: Melbourne Posts: 77 Thanks: 35  Quote:
 
March 9th, 2017, 04:23 AM  #3 
Newbie Joined: Mar 2017 From: South Africa Posts: 2 Thanks: 0  
March 9th, 2017, 12:36 PM  #4  
Senior Member Joined: Sep 2015 From: CA Posts: 1,207 Thanks: 614  Quote:
$p(k) = \binom{n}{k}p^k (1p)^{nk}$ $p(k)=\binom{6}{k}(0.15)^k(0.85)^{6k}$ 1) $p(3) = \binom{6}{3}(0.15)^3(0.85)^3 \approx 0.0414534$ similar for the others. Try again or show how you came about the above results.  

Tags 
distributions, probability 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Probability distributions  proof  ConcreteJungle  Advanced Statistics  0  January 6th, 2016 09:06 AM 
Risk and Probability distributions  chemdude  Advanced Statistics  0  November 6th, 2015 04:35 PM 
Normal Probability distributions  chapsticks  Probability and Statistics  1  October 28th, 2012 07:19 PM 
Probability Distributions  Chee  Probability and Statistics  1  May 31st, 2012 11:48 PM 
Probability Distributions!  Natalie89  Advanced Statistics  1  February 13th, 2011 05:44 PM 