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February 25th, 2017, 08:37 PM  #1 
Newbie Joined: Feb 2017 From: Brazil Posts: 1 Thanks: 0  Combinations where only one element can repeat.
Hi! Let's say I have the letters A, B, C, D. I want to know the number of combinations in the space _, _, _, or 3, where repetitions are allowed. For this, I can apply the formula $\displaystyle C=n ^ x$. In the example would be $\displaystyle C=4 ^ 3=64$. My question is: How do I calculate this, but if only one letter can be repeated? Let's just say "A" can be repeated. For instance: A, A, A A, B, A C, A, A D, A, B (This one does not repeat any, but is part of the result) ... ... Thanks! 
February 25th, 2017, 09:03 PM  #2 
Senior Member Joined: Sep 2015 From: Southern California, USA Posts: 1,397 Thanks: 709 
Does order matter? does $ABD=DAB$ ? If not... this will be the sum of the number of combinations with no repeats plus the number of combinations with 1 repeat. There are $\binom{4}{3}=4 \text{ combinations with 0 repeats.}$ There are $\binom{4}{1}\binom{3}{1}= 12 \text{ combinations with 1 repeat.}$ $\text{Thus a total of 4+12=16 combinations allowing a single repeat.}$ 
February 25th, 2017, 10:53 PM  #3  
Senior Member Joined: Sep 2015 From: Southern California, USA Posts: 1,397 Thanks: 709  Quote:
In this case all we have to do is just subtract off those combos where elements are repeated 3 times. There will be 4 of these. So there will be $4^3  4 = 60$ different combinations allowing a single repeat.  

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combinations, element, repeat 
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