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February 17th, 2017, 04:58 PM  #1 
Senior Member Joined: Oct 2013 From: New York, USA Posts: 561 Thanks: 79  Probability Question With Dice
Dice are rolled until five numbers have been rolled at least twice each. At that time, what is the probaility that the other number has not been rolled and the probability that the other number has been rolled once?

February 17th, 2017, 05:22 PM  #2 
Senior Member Joined: Sep 2015 From: Southern California, USA Posts: 1,604 Thanks: 817 
what? How many and how many sided dice. Do you consider the sum of the dice as the "number" or each of the numbers showing what is "the other number" ? can you rewrite this to be a bit more clear? 
February 18th, 2017, 06:07 AM  #3 
Senior Member Joined: Oct 2013 From: New York, USA Posts: 561 Thanks: 79 
Each die has 6 sides. The amount of rolls depends on what happens. I'm not asking about the sum of the dice. Dice are rolled until five numbers have been rolled at least twice, at which time the other number will have been rolled once or not at all. I'll give examples: 12345612345: 1 through 5 have been rolled twice. At this time the other number, 6, has been rolled once. 1113334445566: 1, 3, 4, 5, and 6 have been rolled at least twice. At this time the other number, 2, has not been rolled. What is the probability of each category? The two probabilities add up to 1. 

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